[Cpp-Programming] Re: Template problem, data member undefined!!!

In the first case, the compilation would fail.

I used gcc 3.4.4 (cygwin) and gcc 4.2.4 (ubuntu)
to compile the code

Here the the error message:

error: 'numArray' was not declared in this scope

On Feb 16, 1:35 am, Ramaraju naga <v.nagaramar...@gmail.com> wrote:
> It is working either case...friend
>
> what was the problem...
>
> Thanks & Regards
> Ramaraju
>
> On Mon, Feb 16, 2009 at 11:51 AM, SeaN <guo.xiaoy...@gmail.com> wrote:
>
> > Please take a look at the following code,
> > my question is: why I have to use
> > Base<_Tp>::datamember to refer the datamember
> > in the base class in the derived class?
> > When I use datamember in the derived class,
> > the compilation would fail.
>
> > I use gcc 3.4.4 (cygwin)
>
> > #include <iostream>
>
> > template <typename _Tp>
> > class Base
> > {
> > protected:
> >    _Tp numArray[3];
> >    Base()
> >    {
> >        numArray[0] = static_cast<_Tp>(1);
> >        numArray[1] = static_cast<_Tp>(11);
> >        numArray[2] = static_cast<_Tp>(111);
> >    };
> > };
>
> > template <typename _Tp>
> > class Deriv: public Base<_Tp> {
> > public:
> >    Deriv() {
>
> >        /* Why the following commented code can not be successfully
> > compiled?
> >         * I got the numArray undefined error !!
> >         *
> >        std::cout << numArray[0] << std::endl;
> >        std::cout << numArray[1] << std::endl;
> >        std::cout << numArray[2] << std::endl;
> >        */
>
> >        /* correct code */
> >        std::cout << Base<_Tp>::numArray[0] << std::endl;
> >        std::cout << Base<_Tp>::numArray[1] << std::endl;
> >        std::cout << Base<_Tp>::numArray[2] << std::endl;
> >    };
> > };
>
> > int main(void)
> > {
> >    Deriv<int> de;
>
> >    return 0;
> > }
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